Question 413 of 521MediumMCQ
The distance of the point −i^+2j^+6k^ from the straight line that passes through the point 2i^+3j^−4k^ and is parallel to the vector 6i^+3j^−4k^ is Solutions · 1
Official solution
AP=(−1−2,2−3,6+4)=(−3,−1,10), d=(6,3,−4).
\[\overrightarrow{AP}\times\vec d=(-26,48,-3),\qquad |\overrightarrow{AP}\times\vec d|=\sqrt{2989},\qquad |\vec d|=\sqrt{61}.\]
\[\text{Distance}=\sqrt{\frac{2989}{61}}=\sqrt{49}=7.\] Answer the question to unlock