Question 400 of 521MediumMCQ
The plane containing the line 1x−1=2y−2=3z−3 and parallel to the line 1x=1y=4z passes through the point: Solutions · 1
Official solution
Plane a(x−1)+b(y−2)+c(z−3)=0 with a+2b+3c=0 (contains the line) and a+b+4c=0 (parallel to (1,1,4)).
\[\frac a{8-3}=\frac b{3-4}=\frac c{1-2}\implies a=5k,\ b=-k,\ c=-k.\]
Plane: 5(x−1)−(y−2)−(z−3)=0⟹5x−y−z=0. Testing (1,0,5): 5−0−5=0 . Answer the question to unlock