If the points (1,1,λ) and (−3,0,1) are equidistant from the plane 3x+4y−12z+13=0, then λ satisfies the equation:
Solutions · 1
Official solution
\[|3+4-12\lambda+13|=|-9+0-12+13|\implies|20-12\lambda|=8\implies \lambda=1\text{ or }\tfrac73.\]
Quadratic with these roots: 3(λ−1)(λ−37)=3λ2−10λ+7=0.