A variable plane passes through a fixed point (3,2,1) and meets the x,y,z axes at A,B,C respectively. A plane is drawn parallel to the yz-plane through A, a second plane parallel to the zx-plane through B, and a third plane parallel to the xy-plane through C. Then the locus of the point of intersection of these three planes is:
Solutions · 1
Official solution
Plane ax+by+cz=1, and the intersection point of the three parallel planes is (a,b,c). Since (3,2,1) lies on the plane:
\[\frac3a+\frac2b+\frac1c=1.\]
Replacing (a,b,c) by the locus variable (x,y,z): x3+y2+z1=1.