If the angle between the lines 2x=2y=1z and −25−x=P7y−14=4z−3 is cos−132, then P is equal to
Solutions · 1
Official solution
Second line direction: (2,7P,4). Setting cosθ=32 with the first line's direction (2,2,1):
\[\frac{4+\tfrac{2P}7+4}{3\sqrt{4+\tfrac{P^2}{49}+16}}=\frac23\implies 4+\frac P7=\sqrt{20+\frac{P^2}{49}}.\]
Squaring: 16+78P+49P2=20+49P2⟹78P=4⟹P=27.