Official solution
Planes bisecting the given planes are
\[{{2x - y + 2z - 4} \over 3} = \pm {{x + 2y + 2z - 2} \over 3}\]
\[ \Rightarrow \] x - 3y = 2 or 3x + y + 4z = 6
Out of the four given points in question's options only (2, -4, 1) lies on the plane 3x + y + 4z = 6