Two lines x-31=y+13=z-6-1 and x+57=y-2-6=z-34 intersect at the point R.

Question

Two lines $\dfrac{x-3}{1}=\dfrac{y+1}{3}=\dfrac{z-6}{-1}$ and $\dfrac{x+5}{7}=\dfrac{y-2}{-6}=\dfrac{z-3}{4}$ intersect at the point $R$. The reflection of $R$ in the $xy$-plane has coordinates:

Accepted Answer

Point on L1 ($$\lambda $$ + 3, 3$$\lambda $$ - 1, - $\lambda $+ 6)

Point on L2 (7$\mu $$-$5,$-$6$\mu $+ 2, 4$\mu $+ 3$ \Rightarrow $$\lambda $+ 3 = 7$\mu $$-$5      . . . . (i)

3$\lambda $$-$1 =$-$6$\mu $+ 2       . . . .(ii)$ \Rightarrow $$\lambda $=$-$1,$\mu $= 1

point R(2,$-$4, 7)

Reflection is (2,$-$4,$-$

Solutions · 1