The plane which bisects the line joining the points (4,-2,3) and (2,4,-1) at right angles …

Question

The plane which bisects the line joining the points $(4,-2,3)$ and $(2,4,-1)$ at right angles also passes through the point:

Accepted Answer

Direction ratios of normal to plane are < 2, --6, 4 >

Also plane passes through (3, 1, 1)

$$ \therefore $$ Equation of plane

2(x--3)--6(y--1)+4(z--1) = 0

$$ \Rightarrow $$ x -- 3y + 2z = 2

By checking all options we can see this equation passes through (4, 0, --1)

Solutions · 1