Question 196 of 521MediumMCQ
The distance of the point (7,−3,−4) from the plane passing through the points (2,−3,1), (−1,1,−2), (3,−4,2) is: Solutions · 1
Official solution
v1=(−3,4,−3), v2=(1,−1,1); normal =v1×v2=(1,0,−1).
\[\text{Plane}:\ (x-2)-(z-1)=0 \implies x-z-1=0.\]
\[d=\frac{|7-(-4)-1|}{\sqrt{2}}=\frac{10}{\sqrt{2}}=5\sqrt{2}.\] Answer the question to unlock