Each of the angles β and γ that a given line makes with the positive y- and z-axes, respectively, is half of the angle α that this line makes with the positive x-axis. Then the sum of all possible values of the angle β (equivalently, all valid solution branches of the governing equation below) is:
Solutions · 1
Official solution
With α=2β=2γ and cos2α+cos2β+cos2γ=1:
\[\cos^2\alpha+2\cos^2\beta=1.\]
Using cosα=2cos2β−1:
\[(2\cos^2\beta-1)^2+2\cos^2\beta=1 \implies (2\cos^2\beta-1)(2\cos^2\beta+1)=0.\]
Since 2cos2β+1=0, we need 2cos2β−1=0⇒cos2β=21, giving the valid solution branches β=4π and β=2π.
Sum =4π+2π=43π.