Question 165 of 521MediumMCQ
The shortest distance between the lines
\[\vec r=\left(\frac13\hat i+2\hat j+\frac83\hat k\right)+\lambda(2\hat i-5\hat j+6\hat k) \quad\text{and}\quad \vec r=\left(-\frac23\hat i-\frac13\hat k\right)+\mu(\hat j-\hat k),\quad \lambda,\mu\in\mathbb R,\]
is:
Solutions · 1
Official solution
a1=(31,2,38), b1=(2,−5,6); a2=(−32,0,−31), b2=(0,1,−1).
\[\vec a_2-\vec a_1=(-1,-2,-3).\]
\[\vec b_1\times\vec b_2=\hat i[(-5)(-1)-6(1)]-\hat j[2(-1)-6(0)]+\hat k[2(1)-(-5)(0)]=(-1,2,2).\]
\[|\vec b_1\times\vec b_2|=\sqrt{1+4+4}=3.\]
\[(\vec a_2-\vec a_1)\cdot(\vec b_1\times\vec b_2)=(-1)(-1)+(-2)(2)+(-3)(2)=1-4-6=-9.\]
\[d=\frac{|-9|}{3}=3.\] Answer the question to unlock